3.22.92 \(\int \frac {(2+3 x)^4}{(1-2 x)^{5/2} (3+5 x)^3} \, dx\) [2192]

Optimal. Leaf size=107 \[ -\frac {73 (2+3 x)^2}{3630 \sqrt {1-2 x} (3+5 x)^2}+\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} (3+5 x)^2}-\frac {1287116+2133933 x}{2196150 \sqrt {1-2 x} (3+5 x)}-\frac {14423 \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )}{366025 \sqrt {55}} \]

[Out]

7/33*(2+3*x)^3/(1-2*x)^(3/2)/(3+5*x)^2-14423/20131375*arctanh(1/11*55^(1/2)*(1-2*x)^(1/2))*55^(1/2)-73/3630*(2
+3*x)^2/(3+5*x)^2/(1-2*x)^(1/2)+1/2196150*(-1287116-2133933*x)/(3+5*x)/(1-2*x)^(1/2)

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Rubi [A]
time = 0.02, antiderivative size = 107, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {100, 154, 149, 65, 212} \begin {gather*} \frac {7 (3 x+2)^3}{33 (1-2 x)^{3/2} (5 x+3)^2}-\frac {73 (3 x+2)^2}{3630 \sqrt {1-2 x} (5 x+3)^2}-\frac {2133933 x+1287116}{2196150 \sqrt {1-2 x} (5 x+3)}-\frac {14423 \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )}{366025 \sqrt {55}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(2 + 3*x)^4/((1 - 2*x)^(5/2)*(3 + 5*x)^3),x]

[Out]

(-73*(2 + 3*x)^2)/(3630*Sqrt[1 - 2*x]*(3 + 5*x)^2) + (7*(2 + 3*x)^3)/(33*(1 - 2*x)^(3/2)*(3 + 5*x)^2) - (12871
16 + 2133933*x)/(2196150*Sqrt[1 - 2*x]*(3 + 5*x)) - (14423*ArcTanh[Sqrt[5/11]*Sqrt[1 - 2*x]])/(366025*Sqrt[55]
)

Rule 65

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 100

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*c -
a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*((e + f*x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] + Dist[1/(b*(b*e - a*
f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d
*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /;
FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 149

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))*((g_.) + (h_.)*(x_)), x_Symbol] :>
Simp[((b^2*c*d*e*g*(n + 1) + a^2*c*d*f*h*(n + 1) + a*b*(d^2*e*g*(m + 1) + c^2*f*h*(m + 1) - c*d*(f*g + e*h)*(
m + n + 2)) + (a^2*d^2*f*h*(n + 1) - a*b*d^2*(f*g + e*h)*(n + 1) + b^2*(c^2*f*h*(m + 1) - c*d*(f*g + e*h)*(m +
1) + d^2*e*g*(m + n + 2)))*x)/(b*d*(b*c - a*d)^2*(m + 1)*(n + 1)))*(a + b*x)^(m + 1)*(c + d*x)^(n + 1), x] -
Dist[(a^2*d^2*f*h*(2 + 3*n + n^2) + a*b*d*(n + 1)*(2*c*f*h*(m + 1) - d*(f*g + e*h)*(m + n + 3)) + b^2*(c^2*f*h
*(2 + 3*m + m^2) - c*d*(f*g + e*h)*(m + 1)*(m + n + 3) + d^2*e*g*(6 + m^2 + 5*n + n^2 + m*(2*n + 5))))/(b*d*(b
*c - a*d)^2*(m + 1)*(n + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n + 1), x], x] /; FreeQ[{a, b, c, d, e, f, g, h
}, x] && LtQ[m, -1] && LtQ[n, -1]

Rule 154

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && ILtQ[m, -1] && GtQ[n, 0]

Rule 212

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {(2+3 x)^4}{(1-2 x)^{5/2} (3+5 x)^3} \, dx &=\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} (3+5 x)^2}-\frac {1}{33} \int \frac {(2+3 x)^2 (43+96 x)}{(1-2 x)^{3/2} (3+5 x)^3} \, dx\\ &=-\frac {73 (2+3 x)^2}{3630 \sqrt {1-2 x} (3+5 x)^2}+\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} (3+5 x)^2}-\frac {\int \frac {(2+3 x) (3056+6117 x)}{(1-2 x)^{3/2} (3+5 x)^2} \, dx}{3630}\\ &=-\frac {73 (2+3 x)^2}{3630 \sqrt {1-2 x} (3+5 x)^2}+\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} (3+5 x)^2}-\frac {1287116+2133933 x}{2196150 \sqrt {1-2 x} (3+5 x)}+\frac {14423 \int \frac {1}{\sqrt {1-2 x} (3+5 x)} \, dx}{732050}\\ &=-\frac {73 (2+3 x)^2}{3630 \sqrt {1-2 x} (3+5 x)^2}+\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} (3+5 x)^2}-\frac {1287116+2133933 x}{2196150 \sqrt {1-2 x} (3+5 x)}-\frac {14423 \text {Subst}\left (\int \frac {1}{\frac {11}{2}-\frac {5 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )}{732050}\\ &=-\frac {73 (2+3 x)^2}{3630 \sqrt {1-2 x} (3+5 x)^2}+\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} (3+5 x)^2}-\frac {1287116+2133933 x}{2196150 \sqrt {1-2 x} (3+5 x)}-\frac {14423 \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )}{366025 \sqrt {55}}\\ \end {align*}

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Mathematica [A]
time = 0.17, size = 63, normalized size = 0.59 \begin {gather*} \frac {\frac {55 \left (-311208+11479257 x+40823468 x^2+34712250 x^3\right )}{(1-2 x)^{3/2} (3+5 x)^2}-86538 \sqrt {55} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )}{120788250} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(2 + 3*x)^4/((1 - 2*x)^(5/2)*(3 + 5*x)^3),x]

[Out]

((55*(-311208 + 11479257*x + 40823468*x^2 + 34712250*x^3))/((1 - 2*x)^(3/2)*(3 + 5*x)^2) - 86538*Sqrt[55]*ArcT
anh[Sqrt[5/11]*Sqrt[1 - 2*x]])/120788250

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Maple [A]
time = 0.11, size = 66, normalized size = 0.62

method	result	size
risch	\(-\frac {34712250 x^{3}[phone] x^{2}[phone] x -311208}{2196150 \left (3+5 x \right )^{2} \sqrt {1-2 x}\, \left (-1+2 x \right )}-\frac {14423 \arctanh \left (\frac {\sqrt {55}\, \sqrt {1-2 x}}{11}\right ) \sqrt {55}}{20131375}\)	\(58\)
derivativedivides	\(\frac {\frac {5 \left (1-2 x \right )^{\frac {3}{2}}}{1331}-\frac {277 \sqrt {1-2 x}}{33275}}{\left (-6-10 x \right )^{2}}-\frac {14423 \arctanh \left (\frac {\sqrt {55}\, \sqrt {1-2 x}}{11}\right ) \sqrt {55}}{20131375}+\frac {2401}{7986 \left (1-2 x \right )^{\frac {3}{2}}}-\frac {9261}{29282 \sqrt {1-2 x}}\)	\(66\)
default	\(\frac {\frac {5 \left (1-2 x \right )^{\frac {3}{2}}}{1331}-\frac {277 \sqrt {1-2 x}}{33275}}{\left (-6-10 x \right )^{2}}-\frac {14423 \arctanh \left (\frac {\sqrt {55}\, \sqrt {1-2 x}}{11}\right ) \sqrt {55}}{20131375}+\frac {2401}{7986 \left (1-2 x \right )^{\frac {3}{2}}}-\frac {9261}{29282 \sqrt {1-2 x}}\)	\(66\)
trager	\(\frac {\left (34712250 x^{3}[phone] x^{2}[phone] x -311208\right ) \sqrt {1-2 x}}{2196150 \left (10 x^{2}+x -3\right )^{2}}+\frac {14423 \RootOf \left (\textit {\_Z}^{2}-55\right ) \ln \left (\frac {5 \RootOf \left (\textit {\_Z}^{2}-55\right ) x +55 \sqrt {1-2 x}-8 \RootOf \left (\textit {\_Z}^{2}-55\right )}{3+5 x}\right )}{40262750}\)	\(80\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2+3*x)^4/(1-2*x)^(5/2)/(3+5*x)^3,x,method=_RETURNVERBOSE)

[Out]

100/14641*(11/20*(1-2*x)^(3/2)-3047/2500*(1-2*x)^(1/2))/(-6-10*x)^2-14423/20131375*arctanh(1/11*55^(1/2)*(1-2*
x)^(1/2))*55^(1/2)+2401/7986/(1-2*x)^(3/2)-9261/29282/(1-2*x)^(1/2)

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Maxima [A]
time = 0.52, size = 92, normalized size = 0.86 \begin {gather*} \frac {14423}{40262750} \, \sqrt {55} \log \left (-\frac {\sqrt {55} - 5 \, \sqrt {-2 \, x + 1}}{\sqrt {55} + 5 \, \sqrt {-2 \, x + 1}}\right ) + \frac {17356125 \, {\left (2 \, x - 1\right )}^{3} + 92891843 \, {\left (2 \, x - 1\right )}^{2} + 313347650 \, x - 76780550}{2196150 \, {\left (25 \, {\left (-2 \, x + 1\right )}^{\frac {7}{2}} - 110 \, {\left (-2 \, x + 1\right )}^{\frac {5}{2}} + 121 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^4/(1-2*x)^(5/2)/(3+5*x)^3,x, algorithm="maxima")

[Out]

14423/40262750*sqrt(55)*log(-(sqrt(55) - 5*sqrt(-2*x + 1))/(sqrt(55) + 5*sqrt(-2*x + 1))) + 1/2196150*(1735612
5*(2*x - 1)^3 + 92891843*(2*x - 1)^2 + 313347650*x - 76780550)/(25*(-2*x + 1)^(7/2) - 110*(-2*x + 1)^(5/2) + 1
21*(-2*x + 1)^(3/2))

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Fricas [A]
time = 1.16, size = 99, normalized size = 0.93 \begin {gather*} \frac {43269 \, \sqrt {55} {\left (100 \, x^{4} + 20 \, x^{3} - 59 \, x^{2} - 6 \, x + 9\right )} \log \left (\frac {5 \, x + \sqrt {55} \sqrt {-2 \, x + 1} - 8}{5 \, x + 3}\right ) + 55 \, {\left (34712250 \, x^{3} + 40823468 \, x^{2} + 11479257 \, x - 311208\right )} \sqrt {-2 \, x + 1}}{120788250 \, {\left (100 \, x^{4} + 20 \, x^{3} - 59 \, x^{2} - 6 \, x + 9\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^4/(1-2*x)^(5/2)/(3+5*x)^3,x, algorithm="fricas")

[Out]

1/120788250*(43269*sqrt(55)*(100*x^4 + 20*x^3 - 59*x^2 - 6*x + 9)*log((5*x + sqrt(55)*sqrt(-2*x + 1) - 8)/(5*x
+ 3)) + 55*(34712250*x^3 + 40823468*x^2 + 11479257*x - 311208)*sqrt(-2*x + 1))/(100*x^4 + 20*x^3 - 59*x^2 - 6
*x + 9)

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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)**4/(1-2*x)**(5/2)/(3+5*x)**3,x)

[Out]

Timed out

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Giac [A]
time = 0.61, size = 89, normalized size = 0.83 \begin {gather*} \frac {14423}{40262750} \, \sqrt {55} \log \left (\frac {{\left | -2 \, \sqrt {55} + 10 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {55} + 5 \, \sqrt {-2 \, x + 1}\right )}}\right ) - \frac {343 \, {\left (81 \, x - 2\right )}}{43923 \, {\left (2 \, x - 1\right )} \sqrt {-2 \, x + 1}} + \frac {125 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 277 \, \sqrt {-2 \, x + 1}}{133100 \, {\left (5 \, x + 3\right )}^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^4/(1-2*x)^(5/2)/(3+5*x)^3,x, algorithm="giac")

[Out]

14423/40262750*sqrt(55)*log(1/2*abs(-2*sqrt(55) + 10*sqrt(-2*x + 1))/(sqrt(55) + 5*sqrt(-2*x + 1))) - 343/4392
3*(81*x - 2)/((2*x - 1)*sqrt(-2*x + 1)) + 1/133100*(125*(-2*x + 1)^(3/2) - 277*sqrt(-2*x + 1))/(5*x + 3)^2

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Mupad [B]
time = 1.23, size = 71, normalized size = 0.66 \begin {gather*} \frac {\frac {51793\,x}{9075}+\frac {8444713\,{\left (2\,x-1\right )}^2}{4991250}+\frac {46283\,{\left (2\,x-1\right )}^3}{146410}-\frac {12691}{9075}}{\frac {121\,{\left (1-2\,x\right )}^{3/2}}{25}-\frac {22\,{\left (1-2\,x\right )}^{5/2}}{5}+{\left (1-2\,x\right )}^{7/2}}-\frac {14423\,\sqrt {55}\,\mathrm {atanh}\left (\frac {\sqrt {55}\,\sqrt {1-2\,x}}{11}\right )}{20131375} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*x + 2)^4/((1 - 2*x)^(5/2)*(5*x + 3)^3),x)

[Out]

((51793*x)/9075 + (8444713*(2*x - 1)^2)/4991250 + (46283*(2*x - 1)^3)/146410 - 12691/9075)/((121*(1 - 2*x)^(3/
2))/25 - (22*(1 - 2*x)^(5/2))/5 + (1 - 2*x)^(7/2)) - (14423*55^(1/2)*atanh((55^(1/2)*(1 - 2*x)^(1/2))/11))/201
31375

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